- chenxueze's blog
2042:【例5.10】稀疏矩阵
- 2024-12-23 18:17:11 @
#include<bits/stdc++.h>
using namespace std;
int main() {
int n,m;
cin >> n >> m;
int a[101][101];
for (int i = 1;i <= n; i++) {
for (int j = 1;j <= m; j++) {
cin >> a[i][j];
}
}
for (int i = 1;i <= n; i++) {
for (int j = 1;j <= m; j++) {
if (a[i][j] != 0) {
cout << i << " " << j << " " << a[i][j] << endl;
}
}
}
return 0;
}