- chenxueze's blog
整数解
- 2025-2-5 10:20:15 @
#include<bits/stdc++.h>
using namespace std;
int main () {
int n,m;
int num = 0;
cin >> n >> m;
for (int i = 1;i <= n / 2; i++){
for (int j = 1;j <= n / i; j++) {
if (i + j == m && i * j == m) {
num += 1;
}
}
}
if (num == 0) {
cout << "no";
}
else {
cout << "yes";
}
return 0;
}